0.002x^2+x-148.5=0

Solution for 0.002x^2+x-148.5=0 equation:

0.002x^2+x-148.5=0

a = 0.002; b = 1; c = -148.5;
Δ = b2-4ac
Δ = 12-4·0.002·(-148.5)
Δ = 2.188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2.188}}{2*0.002}=\frac{-1-\sqrt{2.188}}{0.004}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2.188}}{2*0.002}=\frac{-1+\sqrt{2.188}}{0.004}
$